class A
{
void met1() throws Exception
{
System.out.println("A");
}
}
class Throw1 extends A
{
void met1() throws Exception
{
System.out.println("OVERRIDDEN");
}
public static void main(String args[])throws Exception
{
Throw1 o = new Throw1();
o.met1();
}
}
OUTPUT : OVERRIDDEN
If we don’t write throws Exception with main(), there will be a compile error – Unprotected Exception
Same level throws Exception creates no error.
class A
{
void met1() throws Exception
{
System.out.println("A");
}
}
class Throw2 extends A
{
void met1()
{
System.out.println("OVERRIDDEN");
}
public static void main(String args[])
{
Throw2 o = new Throw2();
o.met1();
}
}
OUTPUT : OVERRIDDEN
No error since over ridden method throwing higher level Exception than the over riding method.
class A
{
void met1() throws Exception
{
System.out.println("A");
}
}
class Throw3 extends A
{
void met1() throws RuntimeException
{
System.out.println("OVERRIDDEN");
}
public static void main(String args[])
{
Throw3 o = new Throw3();
o.met1();
}
}
OUTPUT : OVERRIDDEN
No error since the method in super class is throwing Exception of the higher level than the over riding method in the sub class from the Throwable hierarchy.
class A
{
void met1() throws Exception
{
System.out.println("A");
}
}
class Throw4 extends A
{
void met1() throws Throwable
{
System.out.println("OVERRIDDEN");
}
public static void main(String args[])
{
Throw4 o = new Throw4();
o.met1();
}
}
OUTPUT : Compile Error – met1() in Throw4 does not throw Throwable.
Because overriding method is throwing higher level Exception than over method.
